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Question-213550




Question Number 213550 by mr W last updated on 08/Nov/24
Commented by mr W last updated on 08/Nov/24
semicircle
semicircle
Answered by A5T last updated on 08/Nov/24
Commented by A5T last updated on 08/Nov/24
((s−3)/2)=r−3⇒s=2r−3  ((t−6)/2)=r−6⇒t=2r−6  (t−6)^2 +(s−3)^2 =(2r)^2 =4r^2   ⇒(2r−12)^2 +(2r−6)^2 =4r^2   ⇒r^2 −18r+45=0⇒r=3 or 15  t−6>0⇒r=15⇒2r=30
s32=r3s=2r3t62=r6t=2r6(t6)2+(s3)2=(2r)2=4r2(2r12)2+(2r6)2=4r2r218r+45=0r=3or15t6>0r=152r=30
Commented by mr W last updated on 08/Nov/24
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Answered by Spillover last updated on 09/Nov/24
  R²=[R -6]²+ [R -3]²        R² -12R +36 + R² -6R +9  R²=2R² -18R +45   R² -18R +45=0   R=[18+[324 -  180]½]/2     R=[18+12]/2=15  EF=[15+15]=30
R²=[R -6]²+ [R -3]²
R² -12R +36 + R² -6R +9
R²=2R² -18R +45 R² -18R +45=0
R=[18+[324 – 180]½]/2

R=[18+12]/2=15
EF=[15+15]=30

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