Question-213642 Tinku Tara November 12, 2024 Limits 0 Comments FacebookTweetPin Question Number 213642 by universe last updated on 12/Nov/24 Answered by Berbere last updated on 12/Nov/24 an=limN→∞∑Nk=n1k2;∀k⩾n>1k(k−1)⩽k2⩽k(k+1)⇒limN→∞∑Nk=n1k(k−1)⩾an⩾∑∞k=n1k(k+1)=∑∞k=n1k−1k+1=1n1n−1⩾an⩾1n⇒limn→∞n.an=1n2an⩾n⇒limn→∞n2an=+∞ Commented by universe last updated on 12/Nov/24 thankyousomuchsir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Find-the-maximum-value-of-3sin-2-x-8cosx-5-Next Next post: Question-213656 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.