Question Number 213650 by MathematicalUser2357 last updated on 12/Nov/24
$$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{pythagorean}\:\mathrm{theorem}\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} ={c}^{\mathrm{2}} \:\mathrm{exist}. \\ $$
Answered by MathematicalUser2357 last updated on 12/Nov/24
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