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Question Number 214001 by RoseAli last updated on 24/Nov/24
find all solutions of the equation x^2 =x in each of the rings   Z_2    Z_3   and Z_6
findallsolutionsoftheequationx2=xineachoftheringsZ2Z3andZ6
Answered by TonyCWX08 last updated on 24/Nov/24
In Z_2 , Zero Divisor: 1×2=0  x^2 −x=0  x(x−1)=0  x=0 or x=1  But 2(2−1)=2×1=0  So x=2 is also an answer
InZ2,ZeroDivisor:1×2=0x2x=0x(x1)=0x=0orx=1But2(21)=2×1=0Sox=2isalsoananswer
Answered by mehdee7396 last updated on 24/Nov/24
Z_2 ⇒2∣x(x−1)⇒x∈Z  Z_3 ⇒3∣x(x−1)⇒x=3k or x=3k+1  Z_6 ⇒6∣x(x−1)⇒x=3k or  x=3k+1
Z22x(x1)xZZ33x(x1)x=3korx=3k+1Z66x(x1)x=3korx=3k+1

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