Question Number 214005 by RoseAli last updated on 24/Nov/24
$${find}\:{all}\:{zero}\:{divisors}\:{of}\:{Z}_{\mathrm{24}} \\ $$
Answered by TonyCWX08 last updated on 24/Nov/24
$$\mathrm{1}×\mathrm{24} \\ $$$$\mathrm{2}×\mathrm{12} \\ $$$$\mathrm{3}×\mathrm{8} \\ $$$$\mathrm{4}×\mathrm{6} \\ $$$$\mathrm{6}×\mathrm{4} \\ $$$$\mathrm{8}×\mathrm{3} \\ $$$$\mathrm{12}×\mathrm{2} \\ $$$$\mathrm{24}×\mathrm{1} \\ $$$${Correct}\:{me}\:{if}\:{I}'{m}\:{wrong} \\ $$
Commented by dionigi last updated on 24/Nov/24
$${if}\:{you}\:{mean}\:{Z}_{\mathrm{24}} \:=\:\mathbb{Z}/\mathrm{24}\mathbb{Z} \\ $$$${then}\:\mathrm{24}\:\notin\:\mathbb{Z}/\mathrm{24}\mathbb{Z}\: \\ $$$${and}\:{cannot}\:{be}\:{a}\:{zero}\:{divisor}\:{in}\:\mathbb{Z}/\mathrm{24}\mathbb{Z} \\ $$