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Let-y-x-be-the-solution-of-diff-eq-y-cos-x-y-cos-x-y-0-0-Find-y-pi-6-




Question Number 214000 by golsendro last updated on 24/Nov/24
  Let y(x) be the solution of diff eq.    y ′= ((cos x+y)/(cos x)) , y(0)=0    Find y((π/6)).
$$\:\:\mathrm{Let}\:\mathrm{y}\left(\mathrm{x}\right)\:\mathrm{be}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{diff}\:\mathrm{eq}. \\ $$$$\:\:\mathrm{y}\:'=\:\frac{\mathrm{cos}\:\mathrm{x}+\mathrm{y}}{\mathrm{cos}\:\mathrm{x}}\:,\:\mathrm{y}\left(\mathrm{0}\right)=\mathrm{0} \\ $$$$\:\:\mathrm{Find}\:\mathrm{y}\left(\frac{\pi}{\mathrm{6}}\right). \\ $$
Commented by mr W last updated on 24/Nov/24
do you mean cos (x+y) instead of  cos (x)+y ?
$${do}\:{you}\:{mean}\:\mathrm{cos}\:\left({x}+{y}\right)\:{instead}\:{of} \\ $$$$\mathrm{cos}\:\left({x}\right)+{y}\:? \\ $$
Commented by golsendro last updated on 24/Nov/24
 cos (x) + y sir
$$\:\mathrm{cos}\:\left(\mathrm{x}\right)\:+\:\mathrm{y}\:\mathrm{sir} \\ $$
Commented by mr W last updated on 24/Nov/24
then   y′−(y/(cos x))=1  it′s of type y′+p(x)y=q(x)
$${then}\: \\ $$$${y}'−\frac{{y}}{\mathrm{cos}\:{x}}=\mathrm{1} \\ $$$${it}'{s}\:{of}\:{type}\:{y}'+{p}\left({x}\right){y}={q}\left({x}\right) \\ $$
Commented by mr W last updated on 25/Nov/24

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