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Question-214091




Question Number 214091 by 2AR last updated on 27/Nov/24
Answered by A5T last updated on 27/Nov/24
?=(256^(256) )^(1/2^(11) ) =(2^8 )^(2^8 /2^(11) ) =(2^8 )^2^(−3)  =2^(8/8) =2
$$?=\left(\mathrm{256}^{\mathrm{256}} \right)^{\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{11}} }} =\left(\mathrm{2}^{\mathrm{8}} \right)^{\frac{\mathrm{2}^{\mathrm{8}} }{\mathrm{2}^{\mathrm{11}} }} =\left(\mathrm{2}^{\mathrm{8}} \right)^{\mathrm{2}^{−\mathrm{3}} } =\mathrm{2}^{\frac{\mathrm{8}}{\mathrm{8}}} =\mathrm{2} \\ $$

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