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If-x-1-x-1-find-x-61-1-x-61-4-




Question Number 214186 by hardmath last updated on 30/Nov/24
If   x + (1/x) = 1   find   x^(61)  + (1/x^(61) )+ 4  = ?
Ifx+1x=1findx61+1x61+4=?
Answered by Rasheed.Sindhi last updated on 30/Nov/24
x+(1/x)=1; x^(61) +(1/x^(61) )+4=?  x+(1/x)=1⇒x^2 =x−1  x^3 =x^2 −x=(x−1)−x=−1  (x^3 )^(20) =(−1)^(20) =1⇒x^(60) =1     x^(61) +(1/x^(61) )+4=x^(60) .x+(1/(x^(60) .x))+4                   =x+(1/x)+4=1+4=5
x+1x=1;x61+1x61+4=?x+1x=1x2=x1x3=x2x=(x1)x=1(x3)20=(1)20=1x60=1x61+1x61+4=x60.x+1x60.x+4=x+1x+4=1+4=5
Answered by BaliramKumar last updated on 01/Dec/24
x +  (1/x) = 2cos((π/3))  x^(61)  +  (1/x^(61) ) = 2cos(((61π)/3))               x^n  + (1/x^n ) = 2cos(nθ)            x^(61)  +  (1/x^(61) ) = 2cos(((60π + π)/3))   ⇒ 2cos(20π + (π/3))            x^(61)  +  (1/x^(61) ) = 2cos((π/3))  x^(61)  +  (1/x^(61) ) = 1  x^(61)  +  (1/x^(61) ) + 4 = 1 + 4 = 5
x+1x=2cos(π3)x61+1x61=2cos(61π3)xn+1xn=2cos(nθ)x61+1x61=2cos(60π+π3)2cos(20π+π3)x61+1x61=2cos(π3)x61+1x61=1x61+1x61+4=1+4=5

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