evaluate-C-z-2sin-z-2zcos-z-pi-dz-C-2-2sin-z-2zcos-z-pi-dz-C-z-3pi-4-pi-4- Tinku Tara December 3, 2024 None 0 Comments FacebookTweetPin Question Number 214279 by issac last updated on 03/Dec/24 evaluateρ=∮Cz2sin(z)−2zcos(z)−πdz∮C22sin(z)−2zcos(z)−πdzC=∣z−3π4∣=π4 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-214248Next Next post: Question-214281 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.