evaluate-C-z-2-sin-z-2z-cos-z-pi-dz-C-2-2-sin-z-2z-cos-z-pi-dz-where-C-is-the-circle-z-3pi-4-pi-4- Tinku Tara December 6, 2024 None 0 Comments FacebookTweetPin Question Number 214340 by issac last updated on 06/Dec/24 evaluate∮Cz2⋅sin(z)−2z⋅cos(z)−πdz∮C22⋅sin(z)−2z⋅cos(z)−πdzwhereCisthecircle∣z−3π4∣=π4. Answered by MrGaster last updated on 24/Dec/24 ∮Cz2⋅sin(z)−2z⋅cos(z)−πdz∮C22⋅sin(z)−2z⋅cos(z)−πdz=∮Czdz∮C1dz∮Czdz=0⏟=Cauchy,sinegraltheorem2πi⋅Z=02πi⋅Z=0 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: why-differantiable-f-f-is-continious-but-f-is-continous-differantiable-Next Next post: Question-214372 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.