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evaluate-C-z-2-sin-z-2z-cos-z-pi-dz-C-2-2-sin-z-2z-cos-z-pi-dz-where-C-is-the-circle-z-3pi-4-pi-4-




Question Number 214340 by issac last updated on 06/Dec/24
evaluate  ((∮_C  (z/(2∙sin(z)−2z∙cos(z)−π))dz)/(∮_( C)  (2/(2∙sin(z)−2z∙cos(z)−π))dz))  where C is the circle∣z−((3π)/4)∣=(π/4).
evaluateCz2sin(z)2zcos(z)πdzC22sin(z)2zcos(z)πdzwhereCisthecirclez3π4∣=π4.
Answered by MrGaster last updated on 24/Dec/24
∮_C (z/(2∙sin(z)−2z∙cos(z)−π))dz  ∮_C (2/(2∙sin(z)−2z∙cos(z)−π))dz  =((∮_C z dz)/(∮_C 1 dz))  ∮_C z dz=0_(=((Cauchy^, s inegral theorem)/(2πi∙Z)))   =(0/(2πi∙Z))  =0
Cz2sin(z)2zcos(z)πdzC22sin(z)2zcos(z)πdz=CzdzC1dzCzdz=0=Cauchy,sinegraltheorem2πiZ=02πiZ=0

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