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Question Number 214638 by mr W last updated on 14/Dec/24
if the sum of three prime numbers  is 130, what is the possible   maximum of their product?
$${if}\:{the}\:{sum}\:{of}\:{three}\:{prime}\:{numbers} \\ $$$${is}\:\mathrm{130},\:{what}\:{is}\:{the}\:{possible}\: \\ $$$${maximum}\:{of}\:{their}\:{product}? \\ $$
Answered by BaliramKumar last updated on 14/Dec/24
2 + x + y = 130  x + y = 128  for xy_(max)     ⇒       x = y = ((128)/2) = 64  but 64 is not prime so x and y nearest to 64  x = 64−3 = 61  y = 64 + 3 = 67  (2, 61,67)Answer    other pair (2, 19, 109); (2, 31, 97)
$$\mathrm{2}\:+\:{x}\:+\:{y}\:=\:\mathrm{130} \\ $$$${x}\:+\:{y}\:=\:\mathrm{128} \\ $$$${for}\:{xy}_{{max}} \:\:\:\:\Rightarrow\:\:\:\:\:\:\:{x}\:=\:{y}\:=\:\frac{\mathrm{128}}{\mathrm{2}}\:=\:\mathrm{64} \\ $$$${but}\:\mathrm{64}\:{is}\:{not}\:{prime}\:{so}\:{x}\:{and}\:{y}\:{nearest}\:{to}\:\mathrm{64} \\ $$$${x}\:=\:\mathrm{64}−\mathrm{3}\:=\:\mathrm{61} \\ $$$${y}\:=\:\mathrm{64}\:+\:\mathrm{3}\:=\:\mathrm{67} \\ $$$$\left(\mathrm{2},\:\mathrm{61},\mathrm{67}\right){Answer} \\ $$$$ \\ $$$${other}\:{pair}\:\left(\mathrm{2},\:\mathrm{19},\:\mathrm{109}\right);\:\left(\mathrm{2},\:\mathrm{31},\:\mathrm{97}\right) \\ $$
Commented by mr W last updated on 14/Dec/24
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