log-2-x-log-3-x-1-5-x-

Question Number 215089 by golsendro last updated on 28/Dec/24

\log_{2} x + \log_{3} (x + 1) = 5

x = ?

Answered by efronzo1 last updated on 28/Dec/24

\log_{3} (x + 1) - 2 = 3 - \log_{2} x

\log_{3} (\frac{x + 1}{9}) = \log_{2} (\frac{8}{x})

\log_{3} (1) = \log_{2} (1) = 0

\frac{x + 1}{9} = 1 and \frac{8}{x} = 1

x = 8

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