Question Number 215092 by BaliramKumar last updated on 28/Dec/24
![](https://www.tinkutara.com/question/35857.png)
Commented by BaliramKumar last updated on 28/Dec/24
![I want to find the value of a and b](https://www.tinkutara.com/question/Q215093.png)
Commented by BaliramKumar last updated on 28/Dec/24
![a^3 −b^3 = 125 a^2 −b^2 = 25 a+b = 5 a^2 + ab + b^(2 ) = ?](https://www.tinkutara.com/question/Q215097.png)
Answered by Rasheed.Sindhi last updated on 28/Dec/24
![a^2 −b^2 =25⇒(a−b)(a+b)=25 (a−b)(5)=25⇒a−b=5 { ((a+b=5)),((a−b=5)) :}⇒a=5,b=0 a^2 +ab+b^2 =5^2 +5×0+0^2 =25](https://www.tinkutara.com/question/Q215099.png)
Commented by A5T last updated on 28/Dec/24
![We can also do this,so we get a contradiction. a^3 −b^3 =(a−b)(a^2 +ab+b^2 )=625 a^2 −b^2 =(a−b)(a+b)=25 a+b=5⇒a−b=((25)/5)=5 ⇒a^2 +ab+b^2 =((625)/5)=125](https://www.tinkutara.com/question/Q215100.png)
Commented by Frix last updated on 28/Dec/24
![We′ve got 3 equations for 2 unknowns and all must be satisfied. (1) b=5−a (2) a^2 =25+b^2 a^2 =25+(5−a)^2 a^2 =50−10a+a^2 ⇒ a=5 ⇒ b=0 (3) Test a^3 −b^3 =625 ⇒ wrong ⇒ No solution](https://www.tinkutara.com/question/Q215102.png)
Commented by BaliramKumar last updated on 29/Dec/24
![i think question is wrong](https://www.tinkutara.com/question/Q215115.png)
Commented by Rasheed.Sindhi last updated on 29/Dec/24
![I think that the question has come before this time also.](https://www.tinkutara.com/question/Q215118.png)
Commented by A5T last updated on 29/Dec/24
![Q211393](https://www.tinkutara.com/question/Q215122.png)
Commented by Frix last updated on 29/Dec/24
![A question can not be wrong. The proposed answers are wrong.](https://www.tinkutara.com/question/Q215132.png)