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Question-215107




Question Number 215107 by arkanmathematics63 last updated on 28/Dec/24
Commented by arkanmathematics63 last updated on 28/Dec/24
C is the combination
$${C}\:{is}\:{the}\:{combination} \\ $$
Commented by mr W last updated on 29/Dec/24
some people mean C_n ^k =((n!)/(k!(n−k)!))  while other people mean C_k ^n =((n!)/(k!(n−k)!)).  what do you mean? red or blue?
$${some}\:{people}\:{mean}\:{C}_{{n}} ^{{k}} =\frac{{n}!}{{k}!\left({n}−{k}\right)!} \\ $$$${while}\:{other}\:{people}\:{mean}\:{C}_{{k}} ^{{n}} =\frac{{n}!}{{k}!\left({n}−{k}\right)!}. \\ $$$${what}\:{do}\:{you}\:{mean}?\:{red}\:{or}\:{blue}? \\ $$
Commented by Ghisom last updated on 29/Dec/24
the blue one has no solution at all
$$\mathrm{the}\:\mathrm{blue}\:\mathrm{one}\:\mathrm{has}\:\mathrm{no}\:\mathrm{solution}\:\mathrm{at}\:\mathrm{all} \\ $$
Commented by arkanmathematics63 last updated on 29/Dec/24
Indeed, I′m looking for the solution as well. I tried to use the red one but I couldn′t reach any thing.
$${Indeed},\:{I}'{m}\:{looking}\:{for}\:{the}\:{solution}\:{as}\:{well}.\:{I}\:{tried}\:{to}\:{use}\:{the}\:{red}\:{one}\:{but}\:{I}\:{couldn}'{t}\:{reach}\:{any}\:{thing}. \\ $$

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