Let-two-roots-of-the-equation-x-2-2mx-m-2-2m-3-0-is-For-lt-2-Find-2-Using-m-3-If-2-Solve-for-m-If-you-don-t-solve-it-I-will-force-you-to-solve-

Question Number 215168 by MathematicalUser2357 last updated on 30/Dec/24

Let two roots of the equation x^{2} + 2 m x + m^{2} - 2 m + 3 = 0 is α, β (For α < β),

(2) Find {(α - β)}^{2} Using m .

(3) If β - α = 2, Solve for m .

If you {don}^{'} t solve it, I will force you to solve .

Answered by A5T last updated on 30/Dec/24

α + β = - 2 m; α β = m^{2} - 2 m + 3

{(α - β)}^{2} = {(α + β)}^{2} - 4 α β = 8 m - 12

β - α = 2 \Rightarrow {(α - β)}^{2} = 4 = 8 m - 12 \Rightarrow m = 2

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