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0-Ei-x-lnxdx-




Question Number 215186 by MrGaster last updated on 31/Dec/24
∫_0 ^∞ Ei(−x)lnxdx
$$\int_{\mathrm{0}} ^{\infty} {Ei}\left(−{x}\right)\mathrm{ln}{xdx} \\ $$
Answered by MathematicalUser2357 last updated on 31/Dec/24
=1+𝛄 (≈1.57722)
$$=\mathrm{1}+\boldsymbol{\gamma}\:\left(\approx\mathrm{1}.\mathrm{57722}\right) \\ $$

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