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abac-dc-2-d-ab-c-c-2-ac-abac-




Question Number 215272 by Rasheed.Sindhi last updated on 02/Jan/25
 { ((abac^(−) =(dc^(−) )^2 )),((d=((ab^(−) )/c))),((c^2 =ac^(−) )) :}  abac^(−) =?
{abac=(dc)2d=abcc2=acabac=?
Answered by A5T last updated on 02/Jan/25
c^2 =ac^(−) ⇒c=0,1, 5 or 6    ;   d=((ab^(−) )/c)⇒c≠0  c=1⇒a=0⇒d=b  ⇒100b+1=(10d+1)^2 ⇒100b+1=100b^2 +1+20b  ⇒100b^2 −80b=0⇒b=0⇒d=0  a=b=d=0;c=1⇒abac^(−) =0001    c=5⇒a=2⇒5d=20+b⇒(d,b)=(4,0);(5,5)  Checking⇒(d,b)=(4,0)⇒abac^(−) =2025    c=6⇒a=3⇒6d=30+b⇒(d,b)=(5,0),(6,6)  Checking⇒ None works    ⇒abac^(−) =2025 or 0001
c2=acc=0,1,5or6;d=abcc0c=1a=0d=b100b+1=(10d+1)2100b+1=100b2+1+20b100b280b=0b=0d=0a=b=d=0;c=1abac=0001c=5a=25d=20+b(d,b)=(4,0);(5,5)Checking(d,b)=(4,0)abac=2025c=6a=36d=30+b(d,b)=(5,0),(6,6)CheckingNoneworksabac=2025or0001
Commented by Rasheed.Sindhi last updated on 02/Jan/25
Happy 2025 sir!  Thanks for nice answer!
Happy2025sir!Thanksforniceanswer!
Commented by A5T last updated on 02/Jan/25
Same to you, thanks.
Sametoyou,thanks.

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