Question Number 215313 by AlagaIbile last updated on 02/Jan/25
Answered by mr W last updated on 02/Jan/25
$$\angle{ABD}=\mathrm{135}° \\ $$$$\Rightarrow\angle{CBD}=\mathrm{45}° \\ $$$$\Rightarrow{CD}={CB}=\mathrm{2} \\ $$$$\Rightarrow{AD}=\sqrt{\left(\mathrm{12}+\mathrm{2}\right)^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} }=\mathrm{10}\sqrt{\mathrm{2}} \\ $$$$\Rightarrow{x}=\frac{{AD}}{\:\sqrt{\mathrm{2}}}=\mathrm{10}\:\checkmark \\ $$
Answered by cherokeesay last updated on 02/Jan/25
