Question Number 215372 by Tawa11 last updated on 04/Jan/25
Answered by TonyCWX08 last updated on 04/Jan/25
Commented by TonyCWX08 last updated on 04/Jan/25
$$\left(\alpha+\beta\right)+\left(\Omega+\gamma\right)=\left(\alpha+\Omega\right)+\left(\beta+\gamma\right) \\ $$$$\mathrm{5}+{A}=\mathrm{4}+\mathrm{8} \\ $$$${A}=\mathrm{7} \\ $$
Commented by Tawa11 last updated on 05/Jan/25
$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate} \\ $$