t-33-ab-t-00-ab-Clearing-up-defintions-t-33-a-a-36-3-t-00-a-a-36-0-t-a-a-36-t-a-transformation-of-a-

Question Number 215527 by alephnull last updated on 09/Jan/25

t_{33}^{'} a b + t_{00}^{'} a b = ?

Clearing up defintions :

t_{33}^{'} a = (a - \sqrt{36}) \times 3

t_{00}^{'} a = (a - \sqrt{36}) \times 0

t^{'} a = a - \sqrt{36}

t^{'} a = “ {transformation}^{″} of a

Answered by MrGaster last updated on 10/Jan/25

{\overset{´}{t}}_{33} a = (a - 6) \times 3 = 3 a - 18

{\overset{´}{t}}_{00} a = (a - 6) \times 0 = 0

t^{'} a = a - 6

\Rightarrow t_{33}^{'} a b + t_{00}^{'} a b = (3 a - 18) b + 0

= 3 a b - 18 b

\Rightarrow t_{33}^{'} a b + t_{00}^{'} a b = 3 a b - 18 b ✓

Commented by alephnull last updated on 10/Jan/25

t h a n k y o u s i r w h a t w o u l d i t b e w i t h t h e n o t a t i o n o f t^{'} ?