Question-215708 Tinku Tara January 15, 2025 Algebra 0 Comments FacebookTweetPin Question Number 215708 by essaad last updated on 15/Jan/25 Answered by A5T last updated on 15/Jan/25 (i)+(ii)⇒n3+y3=0⇒(n+y)(n2+y2−ny)=0…(iii)(i)−(ii)⇒4n3−4y3−8n+8y=0⇒n3−y3−2n+2y=0(n−y)(n2+y2+ny−2)=0…(iv)(iii)&(iv)mustbetrueimpliesCaseI:n+y=0andn2+y2+ny−2=0⇒y2=2⇒y=+−2⇒(n,y)=(2,−2);(−2,2)CaseII:n+y=0andn−y=0⇒(n,y)=(0,0)CaseIII:n2+y2−ny=0andn−y=0⇒(n,y)=(0,0)CaseIV:n2+y2−ny=0andn2+y2+ny−2=0⇒(n+y)2=3nyand(n+y)2=ny+2⇒ny=1⇒(n+y)=+−3n,ysatisfyx2+−3x+1=0⇒n,y=(+−)3+−3−4(1)2=(+−)3+−i2(n,y)=(3+i2,3−i2);(−3+i2,−3−i2);(2,−2);(0,0)uptopermutationsinceequationissymmetric. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-215704Next Next post: Determine-a-b-c-Lazy-problem-J181-2-x-3-6x-2-15x-7-x-a-3-bx-c-J182-1-x-3-ax-2-x-1-x-2-bx-c- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.