Question-215943

Question Number 215943 by sitholenonto last updated on 22/Jan/25

Answered by MathematicalUser2357 last updated on 23/Jan/25

Q . 2.1

\sqrt{{(30 - 10 \times \tan 60 °)}^{2} + 10^{2}}

16.14836 ✓

Q . 2.2

\sqrt{{(200 - 400 \times \cos 70 °)}^{2} + {(200 \times \tan 60 ° + 400 \times \sin 70 °)}^{2}}

725.04623 ✓

\tan^{- 1} (\frac{200 \times \tan 60 ° + 400 \times \sin 70 °}{200 - 400 \times \cos 70 °}) / (1 °)

85 (°) ✓

Q . 2.3 (Following Q . 2.2)

\frac{(200 - 400 \times \cos 70 °) \times 20}{10^{3}}

1.263839 ✓