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Question-216153




Question Number 216153 by Tawa11 last updated on 28/Jan/25
Answered by AntonCWX last updated on 29/Jan/25
i=i_L =((12V)/(1Ω+5Ω))=2A  v_C =(1Ω+4Ω)(2A)=10V    W_C  = (1/2)Cv_C ^2  = (1/2)(1)(10^2 ) = 50J  W_L  = (1/2)Li_L ^2  = (1/2)(2)(2^2 ) = 4J
i=iL=12V1Ω+5Ω=2AvC=(1Ω+4Ω)(2A)=10VWC=12CvC2=12(1)(102)=50JWL=12LiL2=12(2)(22)=4J
Commented by Tawa11 last updated on 29/Jan/25
Thanks sir.
Thankssir.

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