Menu Close

Question-216164




Question Number 216164 by BaliramKumar last updated on 29/Jan/25
Answered by AntonCWX last updated on 29/Jan/25
The smallest distance between two sides is 2−1=1  The sum of three sides is 1+2+4=7  Let the fourth side be d  1<d<7  possible values: 2,3,4,5,6  C (5)
Thesmallestdistancebetweentwosidesis21=1Thesumofthreesidesis1+2+4=7Letthefourthsidebed1<d<7possiblevalues:2,3,4,5,6C(5)
Answered by Wuji last updated on 29/Jan/25
a=1,b=2,c=4  1+2+4>d  ⇒7>d  1+2+d>4 ⇒ d>1  1+4+d>2  ⇒d>−3  2+4+d>1 ⇒ d>−5  combing the inequalities  1<d<7  d∈N  2, 3,4,5,6  5 possible integer lengths   for the fourth side
a=1,b=2,c=41+2+4>d7>d1+2+d>4d>11+4+d>2d>32+4+d>1d>5combingtheinequalities1<d<7dN2,3,4,5,65possibleintegerlengthsforthefourthside

Leave a Reply

Your email address will not be published. Required fields are marked *