Question-216279

Question Number 216279 by BaliramKumar last updated on 02/Feb/25

Commented by mairatonny last updated on 02/Feb/25

Commented by mairatonny last updated on 02/Feb/25

someone please do these maths please

Commented by AntonCWX last updated on 03/Feb/25

Y o u {s h o u l d n}^{'} t s e n d y o u r q u e s t i o n s

h e r e i n t h e o t h e r {p e o p l e}^{'} s q u e s t i o n s .

S e n d y o u r s e l f a g a i n .

Answered by mr W last updated on 02/Feb/25

A = a r e a

A = \frac{10 a}{2} = \frac{12 b}{2} = \frac{15 c}{2}

\Rightarrow a = \frac{A}{5}, b = \frac{A}{6}, c = \frac{A}{7.5}

s = \frac{1}{2} (\frac{A}{5} + \frac{A}{6} + \frac{A}{7.5}) = \frac{A}{4}

A = \sqrt{\frac{A}{4} (\frac{A}{4} - \frac{A}{5}) (\frac{A}{4} - \frac{A}{6}) (\frac{A}{4} - \frac{A}{7.5})}

1 = \frac{A \sqrt{7}}{240}

\Rightarrow A = \frac{240}{\sqrt{7}} \Rightarrow a n s w e r b)

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