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Question-216821




Question Number 216821 by BaliramKumar last updated on 22/Feb/25
Answered by AntonCWX08 last updated on 22/Feb/25
AE×BE=25×4=100  AE×BE=100  100  =1×100  =2×50  =4×25  =5×20  =10×10  =20×5  =25×4  =50×2  =100×1    There are 9 values  5 values if consider AE≥BE    min(AB)=20  max(AB)=101
AE×BE=25×4=100AE×BE=100100=1×100=2×50=4×25=5×20=10×10=20×5=25×4=50×2=100×1Thereare9values5valuesifconsiderAEBEmin(AB)=20max(AB)=101
Commented by BaliramKumar last updated on 22/Feb/25
if   AE, BE ∈ R
ifAE,BER

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