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k-1-n-cos-x-2-k-Pn-x-evaluate-Pn-x-and-P-n-x-2-1-

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Question Number 216887 by zetamaths last updated on 23/Feb/25
Π_(k=1) ^n cos((x/2^k ))=Pn(x) evaluate Pn(x) and P_n (x^2 +1)
∏nk=1cos(x2k)=Pn(x)evaluatePn(x)andPn(x2+1)

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