Question-216925

Question Number 216925 by Engr_Jidda last updated on 24/Feb/25

Answered by mehdee7396 last updated on 24/Feb/25

s = \int_{0}^{1} (4 u + 1) d u + \int_{0}^{2} (4 u + 1) d u + \dots + \int_{0}^{10} (4 u + 1) d u

{= {{(2 u^{2} + u)]}_{0}^{1} + (2 u^{2} + u)]}_{0}^{2} + \dots + (2 u^{2} + u)]}_{0}^{10}

= 2 (1^{2} + 2^{2} + \dots + 10^{2}) + (1 + 2 + \dots + 10)

= 2 \times \frac{10 \times 11 \times 21}{6} + \frac{10 \times 11}{2}

= 770 + 55 = 825

Commented by Engr_Jidda last updated on 25/Feb/25

t h a n k s

Commented by Engr_Jidda last updated on 25/Feb/25

t h a n k s

Commented by MathematicalUser2357 last updated on 26/Feb/25

t h a n k s