Question-216953

Question Number 216953 by mustaphapelumi last updated on 25/Feb/25

Commented by Ghisom last updated on 26/Feb/25

or use l^{'} H \hat{o p i t a l}

\lim_{x \to 0} \frac{\sin x}{x} = \lim_{x \to 0} \frac{\frac{d [\sin x]}{d x}}{\frac{d [x]}{d x}} = \lim_{x \to 0} \frac{\cos x}{1} = 1

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