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n-n-1-n-1-n-n-n-n-1-n-1-n-n-n-2-n-1-n-3-

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Question Number 217482 by Rasheed.Sindhi last updated on 14/Mar/25
( n(√((n+1))) +(n+1)(√n) )^n +( n(√((n+1))) −(n+1)(√n) )^n =n^2 (n+1)(n+3)
(n(n+1)+(n+1)n)n+(n(n+1)−(n+1)n)n=n2(n+1)(n+3)

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