Question-217506

Question Number 217506 by Tawa11 last updated on 15/Mar/25

Commented by Tawa11 last updated on 15/Mar/25

2 . 5 m / s^{2} ?

Commented by mr W last updated on 15/Mar/25

y e s, i f t a k e n g = 10 m / s^{2} .

w h a t a r e t h e a c c e l e r a t i o n s o f t h e

p u l l e y s ?

Commented by Tawa11 last updated on 15/Mar/25

Sir, I only solve acceleration of the block .

Show me the acceleration of pulleys sir .

Commented by Tawa11 last updated on 15/Mar/25

sir .

Q 217504, am I correct ?

Commented by mr W last updated on 15/Mar/25

i {d o n}^{'} t u n d e r s t a n d t h e q u e s t i o n .

Commented by Tawa11 last updated on 15/Mar/25

Hahahahahaha .

I think the question is missing a

parameter .

Commented by Tawa11 last updated on 15/Mar/25

Thanks sir .

Answered by mr W last updated on 15/Mar/25

Commented by mr W last updated on 15/Mar/25

2 F_{1} = F = 100 \Rightarrow F_{1} = 50 N

2 F_{2} = F_{1} = 50 \Rightarrow F_{2} = 25 N

w i t h g = 10 m / s^{2}

F_{1} - m_{1} g = m_{1} a_{1}

a_{1} = \frac{F_{1} - m_{1} g}{m_{1}}

a_{1} = \frac{50 - 1 \times 10}{1} = 40 m / s^{2} (↑)

s i m i l a r l y

a_{2} = \frac{25 - 2 \times 10}{2} = 2.5 m / s^{2} (↑)

a_{3} = \frac{25 - 3 \times 10}{3} = - \frac{5}{3} m / s^{2} (↓)

A_{2} - a_{2} = a_{3} - A_{2}

\Rightarrow A_{2} = \frac{a_{2} + a_{3}}{2} = \frac{2.5 - \frac{5}{3}}{2} = \frac{5}{12} m / s^{2} (↑)

A_{1} - a_{1} = A_{2} - A_{1}

\Rightarrow A_{1} = \frac{a_{1} + A_{2}}{2} = \frac{40 + \frac{5}{12}}{2} = 20 \frac{5}{24} m / s^{2} (↑)

Commented by Tawa11 last updated on 15/Mar/25

God bless you sir .

I really appreciate you sir .

Commented by Tawa11 last updated on 15/Mar/25

For mass 3 kg = {5 ms}^{- 1}

For mas 2 kg = 2.5 {ms}^{- 1}

for mass 1 kg = 3 . {75 ms}^{- 1}

Commented by mr W last updated on 15/Mar/25

w r o n g!

Commented by Tawa11 last updated on 15/Mar/25

I will try more

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