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Question-217506




Question Number 217506 by Tawa11 last updated on 15/Mar/25
Commented by Tawa11 last updated on 15/Mar/25
2.5m/s^2  ?
2.5m/s2?
Commented by mr W last updated on 15/Mar/25
yes, if taken g=10 m/s^2 .  what are the accelerations of the  pulleys?
yes,iftakeng=10m/s2.whataretheaccelerationsofthepulleys?
Commented by Tawa11 last updated on 15/Mar/25
Sir, I only solve acceleration of the block.  Show me the acceleration of pulleys sir.
Sir,Ionlysolveaccelerationoftheblock.Showmetheaccelerationofpulleyssir.
Commented by Tawa11 last updated on 15/Mar/25
sir.  Q217504, am I correct?
sir.Q217504,amIcorrect?
Commented by mr W last updated on 15/Mar/25
i don′t understand the question.
idontunderstandthequestion.
Commented by Tawa11 last updated on 15/Mar/25
Hahahahahaha.  I think the question is missing a  parameter.
Hahahahahaha.Ithinkthequestionismissingaparameter.
Commented by Tawa11 last updated on 15/Mar/25
Thanks sir.
Thankssir.
Answered by mr W last updated on 15/Mar/25
Commented by mr W last updated on 15/Mar/25
2F_1 =F=100 ⇒F_1 =50 N  2F_2 =F_1 =50 ⇒F_2 =25 N  with g=10 m/s^2   F_1 −m_1 g=m_1 a_1   a_1 =((F_1 −m_1 g)/m_1 )  a_1 =((50−1×10)/1)=40 m/s^2  (↑)  similarly  a_2 =((25−2×10)/2)=2.5 m/s^2   (↑)  a_3 =((25−3×10)/3)=−(5/3) m/s^2   (↓)    A_2 −a_2 =a_3 −A_2    ⇒A_2 =((a_2 +a_3 )/2)=((2.5−(5/3))/2)=(5/(12)) m/s^2   (↑)    A_1 −a_1 =A_2 −A_1   ⇒A_1 =((a_1 +A_2 )/2)=((40+(5/(12)))/2)=20(5/(24)) m/s^2   (↑)
2F1=F=100F1=50N2F2=F1=50F2=25Nwithg=10m/s2F1m1g=m1a1a1=F1m1gm1a1=501×101=40m/s2()similarlya2=252×102=2.5m/s2()a3=253×103=53m/s2()A2a2=a3A2A2=a2+a32=2.5532=512m/s2()A1a1=A2A1A1=a1+A22=40+5122=20524m/s2()
Commented by Tawa11 last updated on 15/Mar/25
God bless you sir.  I really appreciate you sir.
Godblessyousir.Ireallyappreciateyousir.
Commented by Tawa11 last updated on 15/Mar/25
For mass 3kg  =  5ms^(−1)   For mas 2kg  =  2.5 ms^(−1)   for mass 1kg  =  3.75ms^(−1)
Formass3kg=5ms1Formas2kg=2.5ms1formass1kg=3.75ms1
Commented by mr W last updated on 15/Mar/25
wrong!
wrong!
Commented by Tawa11 last updated on 15/Mar/25
I will try more
Iwilltrymore

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