Question-217617

Question Number 217617 by chidera last updated on 16/Mar/25

Answered by som(math1967) last updated on 17/Mar/25

P r o b a b i l i t y a p o i n t l i e s △ A D M

= \frac{A r △ A D M}{A B C D} = \frac{1}{4}

△ A D M b u t n o t △ A D N

= \frac{△ D O M}{A B C D} = \frac{1}{8}

n e i t h e r △ A D M n o r △ A D N

= \frac{A r M O N B C}{A B C D} = 1 - \frac{3}{8} = \frac{5}{8}

Commented by som(math1967) last updated on 17/Mar/25