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Question-217686




Question Number 217686 by mnjuly1970 last updated on 18/Mar/25
Commented by mnjuly1970 last updated on 18/Mar/25
     why      BC=CF  ?    ⇑⇑⇑         and  find the value of    ” x ”.
whyBC=CF?⇑⇑⇑andfindthevalueofx.
Commented by mr W last updated on 18/Mar/25
you meant BC=BF?
youmeantBC=BF?
Commented by mnjuly1970 last updated on 18/Mar/25
yes yes sir .my mistake.. ⋛
yesyessir.mymistake..
Answered by mr W last updated on 19/Mar/25
Commented by mr W last updated on 19/Mar/25
in ΔADE:  45°+β+α=90°  ⇒β+α=45°  in ΔCBF:  α+β=45° ⇒BC=BF=3  CA=(√(5^2 +3^2 ))=(√(34))  say R=radius of quarter circle  ((ED)/(DC+CA))=((CB)/(BA))  (R/(R+(√(34))))=(3/5)  ⇒R=((3(√(34)))/2)  ((AE)/(ED))=((CA)/(CB))  ((x+3+5)/((3(√(34)))/2))=((√(34))/3)  ⇒x=9  ✓
inΔADE:45°+β+α=90°β+α=45°inΔCBF:α+β=45°BC=BF=3CA=52+32=34sayR=radiusofquartercircleEDDC+CA=CBBARR+34=35R=3342AEED=CACBx+3+53342=343x=9

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