a-b-c-abc-a-2-b-2-c-2-49-ab-bc-ca- Tinku Tara March 19, 2025 Algebra 0 Comments FacebookTweetPin Question Number 217735 by ArshadS last updated on 19/Mar/25 a+b+c=abca2+b2+c2=49ab+bc+ca=?.. Commented by mr W last updated on 19/Mar/25 thereisnouniquesolution.maybeyoushouldask(ab+bc+ca)min=?or(ab+bc+ca)max=? Answered by mr W last updated on 20/Mar/25 assumea,b,c∈Rsayu=a+b,v=abthenwehavea+b−abc=−c⇒u−cv=−c…(i)(a+b)2−2ab=49−c2⇒u2−2v=49−c2…(ii)wecansolveforu,vintermsofc.cu2−2u−c(51−c2)=0⇒u=1±1+c2(51−c2)c⇒v=uc+1=2±1+c2(51−c2)1+c2(51−c2)⩾0c4−51c2−1⩽0⇒51−512+42<0⩽c2⩽51+512+42⇒−51+26052⩽c⩽51+26052≈7.143says=ab+bc+ca,thens=ab+(a+b)c=v+cu=3±21+c2(51−c2)weseesisnotunique.butc2(51−c2)⩽(c2+51−c22)2=5124wehaves=3+21+c2(51−c2)⩽3+21+5124i.e.smax=3+21+5124=3+2605similarlys=3−21+c2(51−c2)⩾3−21+5124i.e.smin=3−21+5124=3−2605summary:withgivenconditionswecannotuniquelydeterminea,b,candab+bc+ca,butwecansaythat−51+26052⩽a,b,c⩽51+26052≈7.1433−2605⩽ab+bc+ca⩽3+2605 Commented by ArshadS last updated on 22/Mar/25 Nicesir,thanksalot! Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: x-1-x-3-x-5-1-x-5-Next Next post: Question-217733 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.