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Let-a-b-c-be-distinct-real-numbers-such-that-a-b-c-b-c-a-c-a-b-0-then-prove-that-a-b-c-2-b-c-a-2-c-a-b-2-0-




Question Number 217764 by ArshadS last updated on 20/Mar/25
  Let a, b, c be distinct real numbers such that  (a/(b−c))+(b/(c−a))+(c/(a−b))=0  then prove that  (a/((b−c)^2 ))+(b/((c−a)^2 ))+(c/((a−b)^2 ))=0
Leta,b,cbedistinctrealnumberssuchthatabc+bca+cab=0thenprovethata(bc)2+b(ca)2+c(ab)2=0
Answered by vnm last updated on 20/Mar/25
Let P(a,b,c)=a(c−a)(a−b)+b(a−b)(b−c)+c(b−c)(c−a)  and Q(a,b,c)=a(c−a)^2 (a−b)^2 +b(a−b)^2 (b−c)^2 +c(b−c)^2 (c−a)^2 .  Then Q(a,b,c)=P(a,b,c)(−a^2 −b^2 −c^2 +bc+ca+ab).  It′s not obvious, of course, but can be checked.  So if P(a,b,c)=0 then Q(a,b,c)=0.
LetP(a,b,c)=a(ca)(ab)+b(ab)(bc)+c(bc)(ca)andQ(a,b,c)=a(ca)2(ab)2+b(ab)2(bc)2+c(bc)2(ca)2.ThenQ(a,b,c)=P(a,b,c)(a2b2c2+bc+ca+ab).Itsnotobvious,ofcourse,butcanbechecked.SoifP(a,b,c)=0thenQ(a,b,c)=0.

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