Question-217949

Question Number 217949 by hardmath last updated on 23/Mar/25

Commented by hardmath last updated on 23/Mar/25

x^{2} + y^{2} + z^{2} = ?

Answered by A5T last updated on 23/Mar/25

\frac{\sin 90 °}{x} = \frac{\sin 70 °}{1} \Rightarrow x = \frac{1}{\sin 70 °}

Similarly, we get y = \frac{1}{\sin 50 °}; z = \frac{1}{\sin 10 °}

\Rightarrow x^{2} + y^{2} + z^{2} = \frac{1}{\sin^{2} 50 °} + \frac{1}{\sin^{2} 10 °} + \frac{1}{\sin^{2} 70} = 36

Facebook Tweet Pin