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if-x-2-y-2-z-2-1-maximum-value-xy-2yz-




Question Number 218005 by jacklau last updated on 25/Mar/25
       if x^2 +y^2 +z^2 =1,    maximum value xy+2yz = ...
ifx2+y2+z2=1,maximumvaluexy+2yz=
Commented by Ghisom last updated on 26/Mar/25
I get  −((√5)/2)≤(x+2z)y≤((√5)/2)
Iget52(x+2z)y52
Commented by mr W last updated on 26/Mar/25
yes. this is correct. maximum is at  x=(1/( (√(10)))), y=(1/( (√2))), z=(2/( (√(10))))
yes.thisiscorrect.maximumisatx=110,y=12,z=210

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