e-st-J-t-dt-s-s-2-1-s-2-1-R-d-ds-e-st-J-t-dt-s-s-2-1-s-s-2-1-s-2-1-3-and-d-ds-e-st-J-t-dt- Tinku Tara March 26, 2025 None 0 Comments FacebookTweetPin Question Number 218043 by SdC355 last updated on 27/Mar/25 ∫e−stJν(t)dt=(s+s2+1)−νs2+1.ν∈R+dds∫e−stJν(t)dt=(s+s2+1)−ν(s+νs2+1)(s2+1)3anddds∫e−stJν(t)dt=−∫te−stJν(t)dt∫te−tJ−12(t)dt=−(1+2)12(1−122)23 Answered by SdC355 last updated on 27/Mar/25 Q218025 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-218021Next Next post: I-0-te-t-J-1-2-t-dt- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.