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determinant-1-0-0-0-1-1-1-0-0-0-0-1-1-0-0-0-0-1-1-0-0-0-0-1-1-1-0-0-0-1-




Question Number 218119 by MrGaster last updated on 30/Mar/25
 determinant ((ε,1,0,0,0,1),(1,ε,1,0,0,0),(0,1,ε,1,0,0),(0,0,1,ε,1,0),(0,0,0,1,ε,1),(1,0,0,0,1,ε))=?
|ε100011ε100001ε100001ε100001ε110001ε|=?
Answered by SdC355 last updated on 30/Mar/25
Holy shit....what is that Lol  But that det{A} is ε^6 −6ε^4 +9ε^2 −4...
Holyshit.whatisthatLolButthatdet{A}isε66ε4+9ε24
Commented by MrGaster last updated on 30/Mar/25
THANK!
THANK!
Commented by Ghisom last updated on 30/Mar/25
the “holy shit” is back. nice.
theholyshitisback.nice.
Answered by Wuji last updated on 30/Mar/25
for the 6×6 matrix  M(ε)=εI+A  for a circulant graph C_n  we have eigenvalues  of A :  2cos(((2πk)/n))   ⇒k=0,1,...,n−1   for n=6    2,1,−1,−2,−1,1  M(ε)=εI + A  ε+2 ,(ε+1)^2 ,(ε−1)^2 ,(ε−2)  detM(ε)=(ε+2)(ε+1)^2 (ε−1)^2 (ε−2)  detM(ε)=(ε^2 −4)(ε^2 −1)^2
forthe6×6matrixM(ε)=εI+AforacirculantgraphCnwehaveeigenvaluesofA:2cos(2πkn)k=0,1,,n1forn=62,1,1,2,1,1M(ε)=εI+Aε+2,(ε+1)2,(ε1)2,(ε2)detM(ε)=(ε+2)(ε+1)2(ε1)2(ε2)detM(ε)=(ε24)(ε21)2

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