Question Number 66697 by naka3546 last updated on 18/Aug/19
Commented by kaivan.ahmadi last updated on 18/Aug/19
$${lim}_{{x}\rightarrow\frac{\pi}{\mathrm{4}}} \:\frac{−{sin}\left({x}−\frac{\pi}{\mathrm{4}}\right)−\left(\mathrm{1}+{tan}^{\mathrm{2}} {x}\right)}{{cos}\left({x}−\frac{\pi}{\mathrm{4}}\right)}=\frac{\mathrm{0}−\left(\mathrm{1}+\mathrm{1}\right)}{\mathrm{1}}=−\mathrm{2} \\ $$
Answered by Cmr 237 last updated on 18/Aug/19
