Menu Close

tan-2-x-tan-4-x-dx-




Question Number 79485 by ubaydulla last updated on 25/Jan/20
∫(tan^2 x+tan^4 x)dx
$$\int\left(\mathrm{tan}\:^{\mathrm{2}} {x}+\mathrm{tan}\:^{\mathrm{4}} {x}\right){dx} \\ $$
Answered by jagoll last updated on 25/Jan/20
∫ tan^2 x(1+tan^2 x)dx=  ∫tan^2 x d(tan x)= (1/3)tan^3 x+c
$$\int\:\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}\left(\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}\right)\mathrm{dx}= \\ $$$$\int\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{d}\left(\mathrm{tan}\:\mathrm{x}\right)=\:\frac{\mathrm{1}}{\mathrm{3}}\mathrm{tan}\:^{\mathrm{3}} \mathrm{x}+\mathrm{c} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *