Question Number 13978 by tawa tawa last updated on 25/May/17
Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 26/May/17
$$\left.{a}\right){h}^{\mathrm{2}} =\mathrm{13}^{\mathrm{2}} −\left(\mathrm{8}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} \right)/\mathrm{4}=\mathrm{169}−\mathrm{25}=\mathrm{144} \\ $$$$\Rightarrow{h}=\mathrm{12} \\ $$$${tg}\measuredangle{oxz}=\frac{\mathrm{12}}{\mathrm{5}}=\mathrm{2}.\mathrm{4}\Rightarrow\measuredangle{oxz}={tg}^{−\mathrm{1}} \mathrm{2}.\mathrm{4}=\mathrm{67}.\mathrm{38}^{\bullet} \\ $$$$\left.{c}\right){V}=\mathrm{6}×\mathrm{8}×\mathrm{12}=\mathrm{576}\:.\blacksquare \\ $$
Commented by tawa tawa last updated on 26/May/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$