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x-2-2-2-2-2-2-2-2-2-




Question Number 145285 by SinNombre last updated on 03/Jul/21
x=2−2+2−2+2−…+2−2+2=2
$${x}=\mathrm{2}−\mathrm{2}+\mathrm{2}−\mathrm{2}+\mathrm{2}−\ldots+\mathrm{2}−\mathrm{2}+\mathrm{2}=\mathrm{2} \\ $$
Commented by phally last updated on 04/Jul/21
x_1 =2+2+2+...+2 {n+1}  x_2 =−(2+2+2+...2){n}  ⇒x_1 +x_2 =2
$$\mathrm{x}_{\mathrm{1}} =\mathrm{2}+\mathrm{2}+\mathrm{2}+…+\mathrm{2}\:\left\{\mathrm{n}+\mathrm{1}\right\} \\ $$$$\mathrm{x}_{\mathrm{2}} =−\left(\mathrm{2}+\mathrm{2}+\mathrm{2}+…\mathrm{2}\right)\left\{{n}\right\} \\ $$$$\Rightarrow\mathrm{x}_{\mathrm{1}} +\mathrm{x}_{\mathrm{2}} =\mathrm{2} \\ $$

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