Question Number 14297 by Tinkutara last updated on 30/May/17
$$\mathrm{Select}\:\mathrm{the}\:\mathrm{correct}\:\mathrm{formulae}\:\mathrm{for} \\ $$$$\mathrm{uniformly}\:\mathrm{accelerated}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{a} \\ $$$$\mathrm{straight}\:\mathrm{line}\:\left(\mathrm{More}\:\mathrm{than}\:\mathrm{one}\:\mathrm{option}\right. \\ $$$$\left.\mathrm{are}\:\mathrm{correct}\right) \\ $$$$\left(\mathrm{1}\right)\:{v}\:=\:{u}\:+\:{at} \\ $$$$\left(\mathrm{2}\right)\:{s}\:=\:\left(\frac{{u}\:+\:{v}}{\mathrm{2}}\right){t} \\ $$$$\left(\mathrm{3}\right)\:{s}\:=\:{vt}\:−\:\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$$$\left(\mathrm{4}\right)\:{s}\:=\:\frac{{v}^{\mathrm{2}} \:−\:{u}^{\mathrm{2}} }{\mathrm{2}{a}} \\ $$
Commented by Tinkutara last updated on 30/May/17
$$\mathrm{Thanks}\:\mathrm{Sir}! \\ $$
Commented by tawa tawa last updated on 30/May/17
$$\mathrm{The}\:\mathrm{question}\:\mathrm{means},\:\mathrm{which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{is}\:\mathrm{not}\:\mathrm{correct}. \\ $$
Commented by tawa tawa last updated on 30/May/17
$$\mathrm{It}\:\mathrm{should}\:\mathrm{be}\:\mathrm{which}\:\mathrm{one}\:\mathrm{is}\:\mathrm{In}\:\mathrm{correct}\:\mathrm{for}\:\mathrm{a}\:\mathrm{uniformely}\:\mathrm{accelerated}\:\mathrm{motion}\: \\ $$$$\mathrm{in}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line}. \\ $$
Commented by tawa tawa last updated on 30/May/17
$$\mathrm{So}\:\mathrm{if}\:\mathrm{more}\:\mathrm{than}\:\mathrm{one}\:\mathrm{option}\:\mathrm{is}\:\mathrm{correct}. \\ $$$$\mathrm{All}\:\mathrm{other}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{correct}\:\mathrm{except}\:\mathrm{for}\:\mathrm{3} \\ $$
Commented by tawa tawa last updated on 30/May/17
$$\mathrm{1},\:\mathrm{2},\:\mathrm{4}\:\mathrm{are}\:\mathrm{correct}. \\ $$
Commented by Tinkutara last updated on 30/May/17
$$\mathrm{But}\:\mathrm{answer}\:\mathrm{given}\:\mathrm{is}\:\mathrm{all}\:\mathrm{are}\:\mathrm{correct}.\:\mathrm{How}? \\ $$
Commented by tawa tawa last updated on 30/May/17
$$\mathrm{it}\:\mathrm{maybe}\:\mathrm{typing}\:\mathrm{error}.\:\:\mathrm{s}\:=\:\mathrm{ut}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{at}^{\mathrm{2}} \\ $$
Commented by prakash jain last updated on 30/May/17
$${v}={u}+{at} \\ $$$${s}={vt}−\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} =\left({u}+{at}\right){t}−\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$$$={ut}+\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{is}\:\mathrm{also}\:\mathrm{correct} \\ $$