Question Number 145863 by bramlexs22 last updated on 09/Jul/21
Answered by mr W last updated on 09/Jul/21
Commented by mr W last updated on 09/Jul/21
$${via}\:\mathrm{1}:\:{C}_{\mathrm{1}} ^{\mathrm{3}} ×{C}_{\mathrm{1}} ^{\mathrm{4}} =\mathrm{12} \\ $$$${via}\:\mathrm{2}:\:{C}_{\mathrm{2}} ^{\mathrm{4}} ×{C}_{\mathrm{1}} ^{\mathrm{3}} =\mathrm{18} \\ $$$${via}\:\mathrm{3}:\:{C}_{\mathrm{2}} ^{\mathrm{5}} ×{C}_{\mathrm{1}} ^{\mathrm{2}} =\mathrm{20} \\ $$$${via}\:\mathrm{4}:\:{C}_{\mathrm{1}} ^{\mathrm{5}} =\mathrm{5} \\ $$$$\Sigma:\:\mathrm{55}\:{pathes} \\ $$
Commented by mr W last updated on 09/Jul/21
$${or}\:{method}\:\mathrm{2}: \\ $$
Commented by mr W last updated on 09/Jul/21
