Question Number 146096 by mathdanisur last updated on 10/Jul/21
Answered by mindispower last updated on 10/Jul/21
$${tg}\left(\mathrm{2}{a}\right)={tg}\left({a}+{b}+{a}−{b}\right)=\frac{{tg}\left({a}+{b}\right)+{tg}\left({a}−{b}\right)}{\mathrm{1}−{tg}\left({a}+{b}\right){tg}\left({a}−{b}\right)}=\frac{\frac{\mathrm{3}}{\mathrm{2}}}{\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$=\mathrm{3}\Rightarrow\mathrm{2}{tg}\left(\mathrm{2}{a}\right)=\mathrm{6} \\ $$
Commented by mathdanisur last updated on 11/Jul/21
$${cool},\:{thanks}\:{Ser} \\ $$