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Question Number 146141 by Tawa11 last updated on 11/Jul/21
  An incident ray is reflected normally by a plane mirror onto a screen where it forms a bright spot. The mirror and screen are parallel and 1m apart. If the mirror is rotated through 5°, calculate the displacement of the spot
$$ \\ $$An incident ray is reflected normally by a plane mirror onto a screen where it forms a bright spot. The mirror and screen are parallel and 1m apart. If the mirror is rotated through 5°, calculate the displacement of the spot
Commented by mr W last updated on 11/Jul/21
Commented by mr W last updated on 11/Jul/21
d=b tan 2θ=100×tan (2×5)=17.63 cm
$${d}={b}\:\mathrm{tan}\:\mathrm{2}\theta=\mathrm{100}×\mathrm{tan}\:\left(\mathrm{2}×\mathrm{5}\right)=\mathrm{17}.\mathrm{63}\:{cm} \\ $$
Commented by Tawa11 last updated on 11/Jul/21
The diagram explanation is needed if possible please.
$$\mathrm{The}\:\mathrm{diagram}\:\mathrm{explanation}\:\mathrm{is}\:\mathrm{needed}\:\mathrm{if}\:\mathrm{possible}\:\mathrm{please}. \\ $$
Commented by Tawa11 last updated on 11/Jul/21
Thank you sir. God bless you.
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$

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