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ax-by-cz-2-3-and-ab-bc-ac-36abc-find-x-y-z-




Question Number 146913 by mathdanisur last updated on 16/Jul/21
ax=by=cz=(2/3) and ab+bc+ac=36abc  find  x+y+z=?
ax=by=cz=23andab+bc+ac=36abcfindx+y+z=?
Answered by liberty last updated on 16/Jul/21
  { ((ax=(2/3))),((by=(2/3))),((cz=(2/3))) :}   ⇒x+y+z=(2/3)((1/a)+(1/b)+(1/c))                       = (2/3)(((ab+ac+bc)/(abc)))                       = (2/3)(((36abc)/(abc)))=24
{ax=23by=23cz=23x+y+z=23(1a+1b+1c)=23(ab+ac+bcabc)=23(36abcabc)=24
Commented by mathdanisur last updated on 16/Jul/21
thank you Ser
thankyouSer

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