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if-3-a-2-5-3b-1-7-3-2c-find-a-b-c-




Question Number 147231 by mathdanisur last updated on 19/Jul/21
if   3^(a+2)  = 5^(3b−1)  = 7^(3−2c)   find   a∙b∙c = ?
$${if}\:\:\:\mathrm{3}^{\boldsymbol{{a}}+\mathrm{2}} \:=\:\mathrm{5}^{\mathrm{3}\boldsymbol{{b}}−\mathrm{1}} \:=\:\mathrm{7}^{\mathrm{3}−\mathrm{2}\boldsymbol{{c}}} \\ $$$${find}\:\:\:\boldsymbol{{a}}\centerdot\boldsymbol{{b}}\centerdot\boldsymbol{{c}}\:=\:? \\ $$
Answered by Olaf_Thorendsen last updated on 19/Jul/21
3^(a+2)  = 5^(3b−1)  = 7^(3−2c)     The last digit of 5^(3b−1)  is 1 if 3b−1 = 0  or 5 if 3b−1 ≠ 0    But the last digit of 3^(a+2)   and 7^(3−2c)   canno′t be 5.    The only solution is 3b−1 = 0 then  3^(a+2)  = 5^(3b−1)  = 7^(3−2c)  = 1 and  a = −2, b = (1/3), c = (3/2)    abc = −2×(1/3)×(3/2) = −1
$$\mathrm{3}^{{a}+\mathrm{2}} \:=\:\mathrm{5}^{\mathrm{3}{b}−\mathrm{1}} \:=\:\mathrm{7}^{\mathrm{3}−\mathrm{2}{c}} \\ $$$$ \\ $$$$\mathrm{The}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{of}\:\mathrm{5}^{\mathrm{3}{b}−\mathrm{1}} \:\mathrm{is}\:\mathrm{1}\:\mathrm{if}\:\mathrm{3}{b}−\mathrm{1}\:=\:\mathrm{0} \\ $$$$\mathrm{or}\:\mathrm{5}\:\mathrm{if}\:\mathrm{3}{b}−\mathrm{1}\:\neq\:\mathrm{0} \\ $$$$ \\ $$$$\mathrm{But}\:\mathrm{the}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{of}\:\mathrm{3}^{{a}+\mathrm{2}} \:\:\mathrm{and}\:\mathrm{7}^{\mathrm{3}−\mathrm{2}{c}} \\ $$$$\mathrm{canno}'\mathrm{t}\:\mathrm{be}\:\mathrm{5}. \\ $$$$ \\ $$$$\mathrm{The}\:\mathrm{only}\:\mathrm{solution}\:\mathrm{is}\:\mathrm{3}{b}−\mathrm{1}\:=\:\mathrm{0}\:\mathrm{then} \\ $$$$\mathrm{3}^{{a}+\mathrm{2}} \:=\:\mathrm{5}^{\mathrm{3}{b}−\mathrm{1}} \:=\:\mathrm{7}^{\mathrm{3}−\mathrm{2}{c}} \:=\:\mathrm{1}\:\mathrm{and} \\ $$$${a}\:=\:−\mathrm{2},\:{b}\:=\:\frac{\mathrm{1}}{\mathrm{3}},\:{c}\:=\:\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$ \\ $$$${abc}\:=\:−\mathrm{2}×\frac{\mathrm{1}}{\mathrm{3}}×\frac{\mathrm{3}}{\mathrm{2}}\:=\:−\mathrm{1} \\ $$
Commented by mathdanisur last updated on 19/Jul/21
cool Ser thank you
$${cool}\:{Ser}\:{thank}\:{you} \\ $$

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