Question Number 82277 by M±th+et£s last updated on 19/Feb/20
Commented by M±th+et£s last updated on 19/Feb/20
$${find}\:{the}\:{area}\:{of}\:\:{the}\:{rectangle} \\ $$
Commented by mr W last updated on 20/Feb/20
$${is}\:{the}\:{triangle}\:{equilateral}? \\ $$
Commented by M±th+et£s last updated on 20/Feb/20
$${no}\:{its}\:{isosceles}\:{triangle}\: \\ $$
Commented by mr W last updated on 20/Feb/20
$${then}\:{no}\:{unique}\:{solution}! \\ $$$$ \\ $$$${area}\:{of}\:{rectangle}={a}×{b} \\ $$$${but}\:{we}\:{have}\:{only} \\ $$$$\sqrt{\left(\frac{{a}}{\mathrm{6}}\right)^{\mathrm{2}} +{b}^{\mathrm{2}} }=\sqrt{\mathrm{5}} \\ $$$$\frac{{a}^{\mathrm{2}} }{\mathrm{36}}+{b}^{\mathrm{2}} =\mathrm{5} \\ $$